Forum Stowarzyszenie "Rowling" Strona Główna
FAQ :: Szukaj :: Użytkownicy :: Grupy :: Galerie  :: Profil :: Zaloguj się, by sprawdzić wiadomości :: Zaloguj  :: Rejestracja


moncler jackets 10000kN hydraulic master cylinder

Zobacz poprzedni temat :: Zobacz następny temat
Napisz nowy tematOdpowiedz do tematu Forum Stowarzyszenie "Rowling" Strona Główna -> Ważne
Autor Wiadomość
kingloverqui
czarodziej/czarownica



Dołączył: 09 Lis 2010
Posty: 485
Przeczytał: 0 tematów

Ostrzeżeń: 0/3
Skąd: England
Płeć: Kobieta

PostWysłany: Sob 20:35, 15 Sty 2011 Temat postu: moncler jackets 10000kN hydraulic master cylinder

,[link widoczny dla zalogowanych]
10000kN hydraulic master cylinder hydraulic system reliability allocation


795,[link widoczny dla zalogowanych], R = 0.779. R = 09】 I,[link widoczny dla zalogowanych], R = 0.839. Then according to equation (21,[link widoczny dla zalogowanych], (7),[link widoczny dla zalogowanych], fI2) calculated the expected system reliability R = 0609 <090 = R, so need to improve unit reliability reliable re-distribution of the skin 22 on the secluded】 system reliability allocation analysis shows that, This system is a part of the series and parallel redundant systems. Allocated to it for reliability. Must be simplified. I simplified dark as 2. Package of a curse!! Hl a BU L Robinson _ [t port master (c) 2 J1 sail master cylinder system, a very simplified logic rig2Simplifiedlogicchan0nthemaincylindersyslemoftileh) 'drauliepress Xiao Zhao Jing Grade 3 100 (0) kN hydraulic forging press main cylinder First, Figure 205 Reliability Allocation 2 (c) shows the series system reliability distribution. Known system design reliability of 0.90, according to equation (6) can be obtained to allow the system failure rate = 2.107 × 10. . . Also from (4), (Cool obtained three series units allow the failure rate were: = 7.459 × 10. = 1.21x10, 3 {= 1.475x10. Then according to equation (1) can be assigned to allow three units reliability is: R5 = 0.963, d = 0.941, R234d = 0.993. The second step of Figure 2 (b) shows the parallel subsystem reliability distribution. Series system reliability in accordance with the principles of multiplication and the equation (7), calculate the failure probability of parallel subsystems, and two components allow the unit to allow the failure probability was 34 = o. 007, = o. 089,3 = o. 381 According to the principle of parallel distribution system reliability, are listed at = o007 nephew equation l3B: 【, which were 3 and in parallel at the subsystem s {s unit and allow the cell failure probability. Solving this equation we have: 3 = 0.175 at = 0.04 according to equation (7) are the two units were allowed to reliability: R23d = 0.825R {d = 0.96 and then by equation (1) available = 8.16 × 10 The third step of S2, S sub-series consisting of the reliability of mooring allocation from (7) = 0.205 = 0.221 can be obtained according to (9) obtained two subsystems allowable failure probability = 0.084, respectively at the last day = 0.091 according to equation (7) / tll equation (6) are the two subsystems reliability and failure rates were allowed to R2 = 0.916R = 0. 909 = 1.75 × 10:1.9 × 10 Thus, the design of the system reliability has been fully allocated to each component unit. Table 1 lists the system component units of the expected failure rate, estimated by the reliability of distribution reliability and failure rate after allowing the design reliability. Table 1 and reliability of the unit failure rate and distribution of the expected value of the comparative value of Tab1Cont ~ stbctweentheforecastandtheallocationofthefailurerateandthereliabilityofcells3 conclusions can be seen from Table 1, the system requirements to achieve the reliability, we must improve the reliability of each individual component. This requires from two aspects, first, select high quality components to ensure a higher inherent reliability; Second, in the process of using the device should be operating correctly, regularly maintained so as to improve the working environment to ensure that the use of components with high reliability. Mechanized units in order to improve the reliability of components of the work to achieve system design requirements. On-site commissioning test certificate. By two hydraulic cartridge valve system failure probability is low. Stable performance, can be a good option to the system reliability requirements of a reference l Zhao Jing. Such as master cylinder hydraulic system pressure without the FTA analysis. Yanshan University. 】 999.23 (I) 7 a 102 Liu obituary letter but mechanical reliability design, Beijing: China drops Imperial College Press. 19963 Xu lI \19,914 students strong Qi. Zhao Jing one. Hydraulic punching head and other 10000kN Hydraulic System setback surgery transformation. Forging setback surgery. 1998, \Crossing the body of Professor fl transmission and control system fault diagnosis and reliability of research spoon. Responsible for and participation in research projects】 O mining items. Been published and ministerial awards two clamp 30 taken

相关的主题文章:


[link widoczny dla zalogowanych]

[link widoczny dla zalogowanych]

[link widoczny dla zalogowanych]


Post został pochwalony 0 razy
Powrót do góry
Zobacz profil autora
Wyświetl posty z ostatnich:
Napisz nowy tematOdpowiedz do tematu Forum Stowarzyszenie "Rowling" Strona Główna -> Ważne Wszystkie czasy w strefie CET (Europa)
Strona 1 z 1


Skocz do:  
Możesz pisać nowe tematy
Możesz odpowiadać w tematach
Nie możesz zmieniać swoich postów
Nie możesz usuwać swoich postów
Nie możesz głosować w ankietach


fora.pl - załóż własne forum dyskusyjne za darmo
Powered by phpBB (C) 2001, 2005 phpBB Group
Theme Retred created by JR9 for stylerbb.net Bearshare
Regulamin